foreach($arr as &$value)
1.引用赋值符号&,是每次循环的时候,把当前元素变成地址,$value变量就是对应元素的地址,循环结束$value是一个指向最后一个元素的地址
2.当我下次循环,使用了这种方式foreach($arr as $value) ,会出现问题;foreach会把每个元素赋值给后面的$value变量
3.因此,逻辑就变成了,把每个元素修改给原数组的最后一个元素,最后一次循环会一直是前一次的结果
4.最好不用引用传递,用这种形式$arr[$key]改原数组,或者在下次循环时候换一个变量名
$nums=array(1,2,3);foreach($nums as &$v){ var_dump($v);}/*int(1)int(2)int(3)*/var_dump($nums);/*array(3) { [0]=> int(1) [1]=> int(2) [2]=> &int(3)}*/foreach($nums as $v){ var_dump($v);}/*int(1)int(2)int(2)*/【相关教程：PHP视频教程】
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