最近在学习SQL嘛,所以各个地方找题目来练手,毕竟现在能离得开数据库么?
Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
问题：
1 、查询“ 001 ”课程比“ 002 ”课程成绩高的所有学生的学号；
select a.S# from (select s#,score from SC where C#=’001′) a,(select s#,score
from SC where C#=’002′) b
where a.score>b.score and a.s#=b.s#;
2 、查询平均成绩大于60分的同学的学号和平均成绩；
select S#,avg(score)
from sc
group by S# having avg(score) > 60 ;
3 、查询所有同学的学号、姓名、选课数、总成绩；
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#=SC.S#
group by Student.S#,Sname
4 、查询姓“李”的老师的个数；
select count(distinct(Tname))
from Teacher
where Tname like ‘李%’;
5 、查询没学过“叶平”老师课的同学的学号、姓名；
Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=’叶平’);
6 、查询学过“ 001 ”并且也学过编号“ 002 ”课程的同学的学号、姓名；
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#=’001’and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#=’002′);
7 、查询学过“叶平”老师所教的所有课的同学的学号、姓名；
select S#,Sname
from Student
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=’叶平’ group by S# having count(SC.C#)=(select count(C#) from
Course,Teacher where Teacher.T#=Course.T# and Tname=’叶平’));
8 、查询课程编号“ 002 ”的成绩比课程编号“ 001 ”课程低的所有同学的学号、姓名；
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#=’002′) score2
from Student,SC where Student.S#=SC.S# and C#=’001′) S_2 where score2 <score;
9 、查询所有课程成绩小于60分的同学的学号、姓名；
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score> 60 );
10 、查询没有学全所有课的同学的学号、姓名；
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11 、查询至少有一门课与学号为“ 1001 ”的同学所学相同的同学的学号和姓名；
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#=’1001′;
12 、查询至少学过学号为“ 001 ”同学所有一门课的其他同学学号和姓名；
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where S#=’001′);
13 、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩；
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname=’叶平’);
14 、查询和“ 1002 ”号的同学学习的课程完全相同的其他同学学号和姓名；
select S# from SC where C# in (select C# from SC where S#=’1002′)
group by
S# having count(*)=(select count(*) from SC where S#=’1002′);
15 、删除学习“叶平”老师课的SC表记录；
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname=’叶平’;
16 、向SC表中插入一些记录，这些记录要求符合以下条件：没有上过编号“ 003 ”课程的同学学号、 2 、
号课的平均成绩；
Insert SC select S#,’002′,(Select avg(score)
from SC where C#=’002′) from Student where S# not in (Select S# from SC where C#=’002′);
17 、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩，按如下形式显示： 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分
SELECT S# as 学生ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’004′) AS 数据库
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’001′) AS 企业管理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’006′) AS 英语
,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18 、查询各科成绩最高和最低的分：以如下形式显示：课程ID，最高分，最低分
SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score
= (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
19 、按各科平均成绩从低到高和及格率的 百分数 从高到低顺序
SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score), 0 ) AS 平均成绩
, 100 * SUM(CASE WHENisnull(score, 0 )>= 60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHENisnull(score, 0 )>= 60 THEN 1 ELSE
0 END)/COUNT(*) DESC
20 、查询如下课程平均成绩和及格率的百分数(用”1行”显示): 企业管理（ 001 ），马克思（ 002 ），OO& UML （ 003 ），数据库（ 004 ）
SELECT SUM(CASE WHEN C# =’001′ THEN score ELSE 0 END)/SUM(CASE C# WHEN ‘001’ THEN 1 ELSE 0 END) AS 企业管理平均分
, 100 * SUM(CASE WHEN C# = ‘001’ AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = ‘001’ THEN 1 ELSE 0 END
) AS 企业管理及格百分数
,SUM(CASE WHEN C# = ‘002’ THEN score ELSE 0 END)/SUM(CASE C# WHEN ‘002’ THEN 1 ELSE 0 END) AS 马克思平均分
, 100 * SUM(CASE WHEN C# = ‘002’ AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = ‘002’ THEN 1 ELSE 0 END) AS 马克思及格百分数
,SUM(CASE WHEN C# = ‘003’ THEN score ELSE 0 END)/
SUM(CASE C# WHEN ‘003’ THEN 1 ELSE 0 END) AS UML平均分
, 100 * SUM(CASE WHEN C# = ‘003’ AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = ‘003’ THEN 1 ELSE 0 END) AS UML及格百分数
,SUM(CASE WHEN C# = ‘004’ THEN score ELSE 0 END)/SUM(CASE C# WHEN ‘004’ THEN 1 ELSE 0 END) AS 数据库平均分
, 100
* SUM(CASE WHEN C# = ‘004’ AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = ‘004’ THEN 1 ELSE 0 END) AS 数据库及格百分数
FROM SC
21 、查询不同老师所教不同课程平均分从高到低显示
SELECT max(Z.T#) AS 教师ID,MAX(Z.Tname) AS 教师姓名,C.C# AS 课程ＩＤ,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均成绩
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22 、查询如下课程成绩第 3 名到第 6 名的学生成绩单：企业管理（ 001 ），马克思（ 002 ），UML （ 003 ），数据库（ 004 ）
[学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩
SELECTDISTINCT top 3
SC.S# As 学生学号,
Student.Sname AS 学生姓名 ,
T1.score AS 企业管理,
T2.score AS 马克思,
T3.score AS UML,
T4.score AS 数据库,
ISNULL(T1.score, 0 ) + ISNULL(T2.score, 0 ) + ISNULL(T3.score, 0 ) + ISNULL(T4.score, 0 ) as 总分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = ‘001’
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = ‘002’
LEFT JOIN SC AS T3
ON SC.S# =T3.S# AND T3.C# = ‘003’
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = ‘004’
WHERE student.S#=SC.S# and
ISNULL(T1.score, 0 ) + ISNULL(T2.score, 0 ) + ISNULL(T3.score, 0 ) + ISNULL(T4.score, 0 )
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score, 0 ) + ISNULL(T2.score, 0 ) + ISNULL(T3.score, 0 ) + ISNULL(T4.score, 0 )
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C#= ‘k1’
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = ‘k2’
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = ‘k3’
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = ‘k4’
ORDER BY ISNULL(T1.score, 0 ) + ISNULL(T2.score, 0 ) + ISNULL(T3.score, 0 ) + ISNULL(T4.score, 0 ) DESC);
23 、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60]
SELECT SC.C# as 课程ID, Cname
as 课程名称
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 – 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 – 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 – 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Coursewhere SC.C#=Course.C#
GROUP BY SC.C#,Cname;
24 、查询学生平均成绩及其名次
SELECT 1 +(SELECT COUNT( distinct 平均成绩)
FROM (SELECT S#,AVG(score) AS 平均成绩
FROM SC
GROUP BY S#
) AS T1
WHERE 平均成绩 > T2.平均成绩) as 名次,
S# as 学生学号,平均成绩
FROM (SELECT S#,AVG(score) 平均成绩
FROM SC
GROUP BY S#
) AS T2
ORDER BY 平均成绩 desc;
25 、查询各科成绩前三名的记录:(不考虑成绩并列情况)
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C# ORDER BY score DESC
)
ORDER BY t1.C#;
26 、查询每门课程被选修的学生数
select c#,count(S#) from sc group by C#;
27 、查询出只选修了一门课程的全部学生的学号和姓名
select SC.S#,Student.Sname,count(C#) AS 选课数
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)= 1 ;
28 、查询男生、女生人数
Select count(Ssex) as 男生人数 from Student group by Ssex having Ssex=’男’;
Select count(Ssex) as 女生人数 from Student group by Ssex having Ssex=’女’；
29 、查询姓“张”的学生名单
SELECT Sname FROM Student WHERE Sname like ‘张%’;
30 、查询同名同性学生名单，并统计同名人数
select Sname,count(*) from Studentgroup by Sname havingcount(*)> 1 ;;
31 、1981年出生的学生名单(注：Student表中Sage列的类型是datetime)
select Sname, CONVERT(char ( 11 ),DATEPART(year,Sage)) as age
from student
whereCONVERT(char( 11 ),DATEPART(year,Sage))=’1981′;
32 、查询每门课程的平均成绩，结果按平均成绩升序排列，平均成绩相同时，按课程号降序排列
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;
33 、查询平均成绩大于85的所有学生的学号、姓名和平均成绩
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname havingavg(score)> 85 ;
34 、查询课程名称为“数据库”，且分数低于60的学生姓名和分数
Select Sname,isnull(score, 0 )
from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C#and Course.Cname=’数据库’and score < 60 ;
35 、查询所有学生的选课情况；
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
36 、查询任何一门课程成绩在70分以上的姓名、课程名称和分数；
SELECTdistinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>= 70 AND SC.S#=student.S#;
37 、查询不及格的课程，并按课程号从大到小排列
select c# from sc where scor e < 60 order by C# ;
38 、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名；
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score> 80 and C#=’003′;
39 、求选了课程的学生人数
select count(*) from sc;
40 、查询选修“叶平”老师所授课程的学生中，成绩最高的学生姓名及其成绩
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and
C.T#=Teacher.T# and Teacher.Tname=’叶平’ and SC.score=(select max(score)from SC where C#=C.C# );
41 、查询各个课程及相应的选修人数
select count(*) from sc group by C#;
42 、查询不同课程成绩相同的学生的学号、课程号、学生成绩
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;
43 、查询每门功成绩最好的前两名
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
44 、统计每门课程的学生选修人数（超过10人的课程才统计）。要求输出课程号和选修人数，查询结果按人数降序排列，查询结果按人数降序排列，若人数相同，按课程号升序排列
select C# as 课程号,count(*) as 人数
from sc
groupby C#
orderbycount(*) desc,c#
45 、检索至少选修两门课程的学生学号
select S#
from sc
groupby s#
havingcount(*) >= 2
46 、查询全部学生都选修的课程的课程号和课程名
select C#,Cname
from Course
where C# in (select c# from sc groupby c#)
47 、查询没学过“叶平”老师讲授的任一门课程的学生姓名
select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname=’叶平’);
48 、查询两门以上不及格课程的同学的学号及其平均成绩
select S#,avg(isnull(score, 0 )) from SC where S# in (select S# from SC where
score < 60 group by S# having count(*)> 2 )group by S#;
49 、检索“ 004 ”课程分数小于60，按分数降序排列的同学学号
select S# from SC where C#=’004’and score < 60 order by score desc;
50 、删除“ 002 ”同学的“ 001 ”课程的成绩
delete from Sc where S#=’001’and C#=’001′;
