1.int类型和float类型不能匹配
go语言规定不允许在整数型变量和浮点型变量之间进行任何数学运算。错误例子如下：
参考：go语言中文文档：www.topgoer.com
转自：
var n, m = 21, 2.1
// 下面一行会报错：invalid operation: n / m (mismatched types int and float64)
fmt.Println(n / m) 改正结果如下：
var n = 21 / 2.1
fmt.Println(n) 2.int类型和time.Duration类型不能匹配
go语言规定数值运算的操作数必须具有相同的类型，除非该操作包含类型转换或非类型化常量。错误例子如下：
var n = 3
// 下面一行会报错：invalid operation: timeout * time.Millisecond (mismatched types int and time.Duration)
fmt.Println(n * time.Millisecond) 改正结果如下：
// 1. 使用常量
const n = 3
fmt.Println(n * time.Millisecond)
// 2. 使用相同类型
var n time.Duration = 10
fmt.Println(n * time.Millisecond) 3.结构体struct
1）声明指针结构体时，如果未初始化，则初始值为nil，因此只有初始化后，才能访问字段或为字段赋值。例子如下：
type City struct {
Name string
}
var c *City
// 错误用法, 未初始化, c为nil
c.Name = "Osaka"
c = &City{}
// 初始化后，结构体指针指向某个结构体地址，才能访问字段，为字段赋值
c.Name = "Tokyo"
// 因此，常用的做法如下
c := &City{}
c.Name = "London" 2）使用Go内置new()函数，可以分配内存来初始化结构休，并返回分配的内存指针，因为已经初始化了，所以可以直接访问字段。例子如下：
var c = new(City)
c.Name = "NewYork" 3）因为把结构体传给函数是值传递，所以在函数内修改结构体的字段并不会影响原结构体，但如果将指针结构体传给函数，则在函数中使用指针对结构体所做的修改，都会影响到指针指向的结构体。例子如下：
func main() {
c1 := City{}
c2 := new(City)
Change(c1,c2)
fmt.Println(c1,c2)
}
func Change(c1 City,c2 *City){
c1.Name = "Tokyo"
c2.Name = "NewYork"
} 4）结构体不能包含自身，比如City中的字段不能是City类型，但可以是*City，例子如下：
type City struct {
Name string
Next City // 这种形式的定义是错误的
}
type City struct {
Name string
Next *City // 这种形式的定义是正确的
} 其他诸如声明一个map不能立即赋值，类型断言失败会panic，二次关闭一个channel也会panic等比较常见的就暂时不详细介绍啦
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